Colligative Properties

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Colligative Properties :-

Colligative properties are properties of solutions that depends on the ratio of the number of solute particles to the number of solvent molecules in a solution and not on the nature of the chemical species present .

  • The vapour pressure of solution decreases when a non – volatile solute is added to a volatile solvent .
  • There are following colligative properties of solutions which are connected with such decrease of vapour pressure .
  • ( 1 ) Relative lowering of vapour pressure .
  • ( 2 ) Depression of freezing point .
  • ( 3 ) Elevation of boiling point .
  • (4 ) Osmotic pressure.

All these colligative properties have the common characteristics that depend upon the number of Solute particles . since these properties are bound together through their common origin they are called colligative properties .

Relative lowering of Vapour Pressure :-

In a Solution containing several non – volatile solutes , the lowering of the vapour pressure depends on the sum of the mole fraction of different solutes .

PтВБ = XтВБ PтВБтБ░

Reduction of Vapour Pressure of Solvent

тИЖPтВБ = PтВБтБ░ – PтВБ = PтВБтБ░ – PтВБ XтВБ

= PтВБ ( 1 – XтВБ )

Knowing that XтВВ = 1 – XтВБ

тИЖPтВБ = XтВВ PтВБтБ░

The equation can be written as

тИЖPтВБ / PтВБтБ░ = ( PтВБтБ░ – PтВБ ) /PтВБтБ░ = XтВВ

This equation is called relative lowering of Vapour Pressure and is equal to the mole fraction of the Solute .

i . e . ( PтВБтБ░ – PтВВ ) / PтВБ = nтВВ / nтВБ + n┬▓

since XтВВ = nтВВ / nтВБ + nтВВ

Here nтВБ and nтВВ are the number of moles of Solvent and Solute respectively .

For dilute Solution nтВВ << nтВБ

Then

( PтВБтБ░ – PтВБ ) / PтВБ = nтВВ / nтВБ

Or ( PтВБтБ░ – PтВБ ) / PтВБтБ░ = WтВВ X MтВБ / WтВБ x MтВВ

Here WтВБ and WтВВ are the masses , MтВБ and MтВВ are the molar masses of the Solvent and Solute respectively .

Elevation of boiling point :-

The elevation of boiling point also depends on the number of Solute molecules rather than their nature .

A Solution of 1 gm of water boils at 373┬╖52 K at one atmospheric Pressure .

Let TтБ░тВБ be the boiling point of pure Solvent and TтВБ be the boiling point of Solution .

The increase in boiling point

тИЖTтВБ = TтВБ – TтВБтБ░ is known as elevation of boiling point .

  • For dilute Solutions the elevation of boiling point is directly proportional to the molar concentration of the Solute in a Solution .

Thus

тИЖTтВБ ╬▒ m

тИЖTтВБ = KтВБ m

Here m is molality , KтВБ is called boiling point elevation constant its SI unit is K kg molтБ╗┬╣

  • If WтВВ gm of Solute of molar mass MтВВ is dissolved in WтВБ gm of Solvent , then molality

m = ( WтВБ / MтВВ ) / ( WтВБ / 1000 ) = WтВВ x 1000 / MтВВ x WтВБ

Substituting the value of molality in equation

тИЖTтВБ = KтВБ m

тИЖTтВБ = ( KтВБ x WтВВ x 1000 ) / MтВВ x WтВБ

MтВВ = ( KтВБ x WтВВ x 1000 ) / тИЖT x WтВБ

Depression of Freezing point :-

The freezing point of a substance may be defined as the temperature at which the vapour pressure of the substance in its liquid phase is equal to its vapour pressure in the solid phase .

According to Raoult’s law when a non – volatile solid is added to the solvent become equal to that of solid solvent at lower temperature .

Thus the freezing point of the solvent decreases .

Let TтБ░f be the freezing point of pure Solvent and Tf be its freexing point when non- volatile Solute is dissolved in it .

The decrease in freezing point

тИЖTf = TтБ░f – Tf is known as depression in freezing point .

  • Depression of freezing point for dilute Solution ( Ideal Solution ) is directly proportional to molality ( m ) of the Solution

I .e . тИЖTf ╬▒ m

Where Kf is known as freezing point depression constant . The unit molar depression constant is K Kg molтБ╗┬╣ . Its value is depends on the nature of the Solvent .

  • If WтВВ gm of the Solute having molar mass as MтВВ , present in WтВБ gm of Solvent , produce depression in freezing point тИЖTf of the Solvent then molality of the Solute is given by the equation –

m = ( WтВВ / MтВВ ) / WтВБ / 1000

or ( m = WтВВ x 100 ) / MтВВ x WтВБ

Substituting this value of molality in equation тИЖTf = Kf m

тИЖTf = Kf x WтВВ x 1000 / MтВВ x WтВБ

Osmotic Pressure :-

The flow of the solvent from its side to solution side across a semipermeable membrane can stopped if some extra pressure is applied on the solution . This pressure that just stops the flow of solvent is called Osmotic pressure of the solution.

I . e . The Osmotic pressure of a solution is the the excess pressure that must be applied to a solution to prevent osmosis .

Osmosis :-

If the semipermeable membrane is placed between the solvent and solution , the solvent molecules will flow through the membrane from pure solvent to the solution . This process of flow of the solvent is called osmosis .

Semipermeable membrane :-

Semipermeable membrane is the layer that only selected molecules can pass through . It can be both biological and artificial .

Assume that only solvent molecules can pass through these membranes .

  • Osmotic pressure is directly proportional to the molarity ( C ) of the solution at a given temperature ( T ).

I .e .

╧А = C R T

Here ╧А is the Osmotic Pressure and R is the Gas constant .

GRB PHY CHM P2 V03 QB C13 E01 098 Q01
Fig . 1 . Graph between Osmotic Pressure and molality of the Solution .

If nтВВ is moles of Solutes and V is the Volume of Solution then Osmotic Pressure

╧А = nтВВ R T / V

principle permeation water diffusion sugar differences membrane
Fig . 2 . Osmosis process through Semipermeable membrane .

Reverse Osmosis and water purification :-

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Fig . 3 . Reverse Osmosis for Sea Water purification .

The direction of osmosis can be reversed if a pressure larger than the osmotic pressure is applied to the solution side . I . e . the pure solvent flows out of the solution through the semipermeable membrane . This phenomenon is called reverse osmosis .

  • Reverse osmosis is used in desalination of sea water . A schematic set up for the process in the above figure , when pressure more than osmotic pressure is applied , pure water is squeezed out of the sea water through the membrane .
  • The pressure required for the reverse osmosis is quite high .

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